20002301131341 has 4 divisors (see below), whose sum is σ = 26669734841792. Its totient is φ = 13334867420892.

The previous prime is 20002301131339. The next prime is 20002301131349. The reversal of 20002301131341 is 14313110320002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20002301131341 - 2¹ = 20002301131339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20002301131349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3333716855221 + ... + 3333716855226.

It is an arithmetic number, because the mean of its divisors is an integer number (6667433710448).

Almost surely, 2^{20002301131341} is an apocalyptic number.

It is an amenable number.

20002301131341 is a deficient number, since it is larger than the sum of its proper divisors (6667433710451).

20002301131341 is an equidigital number, since it uses as much as digits as its factorization.

20002301131341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6667433710450.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 20002301131341 its reverse (14313110320002), we get a palindrome (34315411451343).

The spelling of 20002301131341 in words is "twenty trillion, two billion, three hundred one million, one hundred thirty-one thousand, three hundred forty-one".