Base | Representation |
---|---|
bin | 10010101000001111… |
… | …000110011100100011 |
3 | 1220122000001012110221 |
4 | 102220033012130203 |
5 | 311431103300120 |
6 | 13104452503511 |
7 | 1305451411042 |
oct | 225017063443 |
9 | 56560035427 |
10 | 20002400035 |
11 | 8534919222 |
12 | 3a6291ab97 |
13 | 1b6a038187 |
14 | d7a74c559 |
15 | 7c10920aa |
hex | 4a83c6723 |
20002400035 has 4 divisors (see below), whose sum is σ = 24002880048. Its totient is φ = 16001920024.
The previous prime is 20002400029. The next prime is 20002400053. The reversal of 20002400035 is 53000420002.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53000420002 = 2 ⋅26500210001.
It is a cyclic number.
It is not a de Polignac number, because 20002400035 - 217 = 20002268963 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20002399991 and 20002400018.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000239999 + ... + 2000240008.
It is an arithmetic number, because the mean of its divisors is an integer number (6000720012).
Almost surely, 220002400035 is an apocalyptic number.
20002400035 is a deficient number, since it is larger than the sum of its proper divisors (4000480013).
20002400035 is an equidigital number, since it uses as much as digits as its factorization.
20002400035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4000480012.
The product of its (nonzero) digits is 240, while the sum is 16.
Adding to 20002400035 its reverse (53000420002), we get a palindrome (73002820037).
The spelling of 20002400035 in words is "twenty billion, two million, four hundred thousand, thirty-five".
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