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2000324114 = 25009199673
BaseRepresentation
bin111011100111010…
…1000011000010010
312011101221222211022
41313032220120102
513044040332424
6530253515442
7100366321505
oct16716503022
95141858738
102000324114
11937149128
12479aa2b82
1325b55ba49
1414d94113c
15ba92895e
hex773a8612

2000324114 has 8 divisors (see below), whose sum is σ = 3001100220. Its totient is φ = 999957376.

The previous prime is 2000324093. The next prime is 2000324129. The reversal of 2000324114 is 4114230002.

It can be written as a sum of positive squares in 2 ways, for example, as 1999610089 + 714025 = 44717^2 + 845^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×20003241142 = 8002593122099769992, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2000324092 and 2000324101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89819 + ... + 109854.

Almost surely, 22000324114 is an apocalyptic number.

2000324114 is a deficient number, since it is larger than the sum of its proper divisors (1000776106).

2000324114 is a wasteful number, since it uses less digits than its factorization.

2000324114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204684.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 2000324114 is about 44724.9831078783. The cubic root of 2000324114 is about 1259.9891058939.

Adding to 2000324114 its reverse (4114230002), we get a palindrome (6114554116).

The spelling of 2000324114 in words is "two billion, three hundred twenty-four thousand, one hundred fourteen".

Divisors: 1 2 5009 10018 199673 399346 1000162057 2000324114