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20004021021211 = 149134255174639
BaseRepresentation
bin1001000110001100011001…
…00100010010101000011011
32121211100212121201112210021
410203012030210102220123
510110221213340134321
6110313415334331311
74133146201106533
oct443061444225033
977740777645707
1020004021021211
1164127263a9867
1222b0ab61b9b37
13b214a9385626
144d22b22c44c3
1524a53cdae941
hex12318c912a1b

20004021021211 has 4 divisors (see below), whose sum is σ = 20138276196000. Its totient is φ = 19869765846424.

The previous prime is 20004021021161. The next prime is 20004021021221. The reversal of 20004021021211 is 11212012040002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20004021021211 - 29 = 20004021020699 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20004021021221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67127587171 + ... + 67127587468.

It is an arithmetic number, because the mean of its divisors is an integer number (5034569049000).

Almost surely, 220004021021211 is an apocalyptic number.

20004021021211 is a deficient number, since it is larger than the sum of its proper divisors (134255174789).

20004021021211 is a wasteful number, since it uses less digits than its factorization.

20004021021211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134255174788.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 20004021021211 its reverse (11212012040002), we get a palindrome (31216033061213).

The spelling of 20004021021211 in words is "twenty trillion, four billion, twenty-one million, twenty-one thousand, two hundred eleven".

Divisors: 1 149 134255174639 20004021021211