Base | Representation |
---|---|
bin | 1001000110001100111011… |
… | …10100101001010100011011 |
3 | 2121211101121210110122222221 |
4 | 10203012131310221110123 |
5 | 10110222311443133430 |
6 | 110313504155324511 |
7 | 4133156314604554 |
oct | 443063564512433 |
9 | 77741553418887 |
10 | 20004310521115 |
11 | 6412864861388 |
12 | 22b0b77150737 |
13 | b2152434804b |
14 | 4d22dc92332b |
15 | 24a5584e757a |
hex | 12319dd2951b |
20004310521115 has 4 divisors (see below), whose sum is σ = 24005172625344. Its totient is φ = 16003448416888.
The previous prime is 20004310521077. The next prime is 20004310521137. The reversal of 20004310521115 is 51112501340002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20004310521115 - 29 = 20004310520603 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20004310521115.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000431052107 + ... + 2000431052116.
It is an arithmetic number, because the mean of its divisors is an integer number (6001293156336).
Almost surely, 220004310521115 is an apocalyptic number.
20004310521115 is a deficient number, since it is larger than the sum of its proper divisors (4000862104229).
20004310521115 is an equidigital number, since it uses as much as digits as its factorization.
20004310521115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4000862104228.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 20004310521115 its reverse (51112501340002), we get a palindrome (71116811861117).
The spelling of 20004310521115 in words is "twenty trillion, four billion, three hundred ten million, five hundred twenty-one thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •