200043323111 has 4 divisors (see below), whose sum is σ = 200074339224. Its totient is φ = 200012307000.

The previous prime is 200043323093. The next prime is 200043323149. The reversal of 200043323111 is 111323340002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200043323111 - 2¹⁸ = 200043060967 is a prime.

It is a super-2 number, since 2×200043323111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200043323171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15498380 + ... + 15511281.

It is an arithmetic number, because the mean of its divisors is an integer number (50018584806).

Almost surely, 2^200043323111 is an apocalyptic number.

200043323111 is a deficient number, since it is larger than the sum of its proper divisors (31016113).

200043323111 is an equidigital number, since it uses as much as digits as its factorization.

200043323111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31016112.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 200043323111 its reverse (111323340002), we get a palindrome (311366663113).

The spelling of 200043323111 in words is "two hundred billion, forty-three million, three hundred twenty-three thousand, one hundred eleven".