2001001113301 has 4 divisors (see below), whose sum is σ = 2001005044704. Its totient is φ = 2000997181900.

The previous prime is 2001001113299. The next prime is 2001001113421. The reversal of 2001001113301 is 1033111001002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2001001113301 - 2¹ = 2001001113299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001001713301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1064515 + ... + 2266096.

It is an arithmetic number, because the mean of its divisors is an integer number (500251261176).

Almost surely, 2^{2001001113301} is an apocalyptic number.

It is an amenable number.

2001001113301 is a deficient number, since it is larger than the sum of its proper divisors (3931403).

2001001113301 is an equidigital number, since it uses as much as digits as its factorization.

2001001113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3931402.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 2001001113301 its reverse (1033111001002), we get a palindrome (3034112114303).

The spelling of 2001001113301 in words is "two trillion, one billion, one million, one hundred thirteen thousand, three hundred one".