200101201221113 has 4 divisors (see below), whose sum is σ = 200200704555408. Its totient is φ = 200001697886820.

The previous prime is 200101201221109. The next prime is 200101201221121. The reversal of 200101201221113 is 311122102101002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200101201221113 - 2² = 200101201221109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200101201221091 and 200101201221100.

It is not an unprimeable number, because it can be changed into a prime (200101201221133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49751664131 + ... + 49751668152.

It is an arithmetic number, because the mean of its divisors is an integer number (50050176138852).

Almost surely, 2^{200101201221113} is an apocalyptic number.

It is an amenable number.

200101201221113 is a deficient number, since it is larger than the sum of its proper divisors (99503334295).

200101201221113 is an equidigital number, since it uses as much as digits as its factorization.

200101201221113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99503334294.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 200101201221113 its reverse (311122102101002), we get a palindrome (511223303322115).

The spelling of 200101201221113 in words is "two hundred trillion, one hundred one billion, two hundred one million, two hundred twenty-one thousand, one hundred thirteen".