Base | Representation |
---|---|
bin | 1011101001011011110… |
… | …1101010110010000011 |
3 | 201010111101210102012111 |
4 | 2322112331222302003 |
5 | 11234301404302120 |
6 | 231531504040151 |
7 | 20312460340060 |
oct | 2722675526203 |
9 | 633441712174 |
10 | 200101244035 |
11 | 77953a32360 |
12 | 32945603057 |
13 | 15b3c2a9ca4 |
14 | 9983717c67 |
15 | 53122c275a |
hex | 2e96f6ac83 |
200101244035 has 64 divisors (see below), whose sum is σ = 301412127744. Its totient is φ = 123890342400.
The previous prime is 200101244023. The next prime is 200101244053. The reversal of 200101244035 is 530442101002.
It is not a de Polignac number, because 200101244035 - 213 = 200101235843 is a prime.
It is a super-3 number, since 3×2001012440353 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200101243997 and 200101244015.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 78254977 + ... + 78257533.
It is an arithmetic number, because the mean of its divisors is an integer number (4709564496).
Almost surely, 2200101244035 is an apocalyptic number.
200101244035 is a deficient number, since it is larger than the sum of its proper divisors (101310883709).
200101244035 is a wasteful number, since it uses less digits than its factorization.
200101244035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3884.
The product of its (nonzero) digits is 960, while the sum is 22.
Adding to 200101244035 its reverse (530442101002), we get a palindrome (730543345037).
The spelling of 200101244035 in words is "two hundred billion, one hundred one million, two hundred forty-four thousand, thirty-five".
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