2001031202013 has 4 divisors (see below), whose sum is σ = 2668041602688. Its totient is φ = 1334020801340.

The previous prime is 2001031201997. The next prime is 2001031202021. The reversal of 2001031202013 is 3102021301002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2001031202013 - 2⁴ = 2001031201997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2001031201983 and 2001031202001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001031202083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333505200333 + ... + 333505200338.

It is an arithmetic number, because the mean of its divisors is an integer number (667010400672).

Almost surely, 2^{2001031202013} is an apocalyptic number.

It is an amenable number.

2001031202013 is a deficient number, since it is larger than the sum of its proper divisors (667010400675).

2001031202013 is an equidigital number, since it uses as much as digits as its factorization.

2001031202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667010400674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 2001031202013 its reverse (3102021301002), we get a palindrome (5103052503015).

The spelling of 2001031202013 in words is "two trillion, one billion, thirty-one million, two hundred two thousand, thirteen".