20010313111 has 4 divisors (see below), whose sum is σ = 20075493592. Its totient is φ = 19945132632.

The previous prime is 20010313079. The next prime is 20010313129. The reversal of 20010313111 is 11131301002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20010313111 - 2⁵ = 20010313079 is a prime.

It is a super-3 number, since 3×20010313111³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20010313091 and 20010313100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20010313511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32589780 + ... + 32590393.

It is an arithmetic number, because the mean of its divisors is an integer number (5018873398).

Almost surely, 2^20010313111 is an apocalyptic number.

20010313111 is a deficient number, since it is larger than the sum of its proper divisors (65180481).

20010313111 is an equidigital number, since it uses as much as digits as its factorization.

20010313111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65180480.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 20010313111 its reverse (11131301002), we get a palindrome (31141614113).

The spelling of 20010313111 in words is "twenty billion, ten million, three hundred thirteen thousand, one hundred eleven".