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200110021405 = 575717429183
BaseRepresentation
bin1011101001011101111…
…1001001101100011101
3201010112000022100111021
42322113133021230131
511234311131141110
6231532420124141
720312625055060
oct2722737115435
9633460270437
10200110021405
1177958987988
1232948536651
1315b410611b8
1499849608d7
155312e582da
hex2e977c9b1d

200110021405 has 8 divisors (see below), whose sum is σ = 274436600832. Its totient is φ = 137218300368.

The previous prime is 200110021259. The next prime is 200110021417. The reversal of 200110021405 is 504120011002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200110021405 - 211 = 200110019357 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2858714557 + ... + 2858714626.

It is an arithmetic number, because the mean of its divisors is an integer number (34304575104).

Almost surely, 2200110021405 is an apocalyptic number.

It is an amenable number.

200110021405 is a deficient number, since it is larger than the sum of its proper divisors (74326579427).

200110021405 is an equidigital number, since it uses as much as digits as its factorization.

200110021405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5717429195.

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 200110021405 its reverse (504120011002), we get a palindrome (704230032407).

The spelling of 200110021405 in words is "two hundred billion, one hundred ten million, twenty-one thousand, four hundred five".

Divisors: 1 5 7 35 5717429183 28587145915 40022004281 200110021405