Base | Representation |
---|---|
bin | 101101011111111110111111… |
… | …010111111001010011001010 |
3 | 222020112022222012020210222011 |
4 | 231133332333113321103022 |
5 | 202212100321143001302 |
6 | 1545333140221050134 |
7 | 60102321066014152 |
oct | 5537767727712312 |
9 | 866468865223864 |
10 | 200110032000202 |
11 | 5884120822a705 |
12 | 1a53a7b89b694a |
13 | 87873ab2b12cc |
14 | 375b53d177762 |
15 | 18204c3da85d7 |
hex | b5ffbf5f94ca |
200110032000202 has 4 divisors (see below), whose sum is σ = 300165048000306. Its totient is φ = 100055016000100.
The previous prime is 200110032000187. The next prime is 200110032000227. The reversal of 200110032000202 is 202000230011002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 126729752719761 + 73380279280441 = 11257431^2 + 8566229^2 .
It is a super-3 number, since 3×2001100320002023 (a number of 44 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50027508000049 + ... + 50027508000052.
Almost surely, 2200110032000202 is an apocalyptic number.
200110032000202 is a deficient number, since it is larger than the sum of its proper divisors (100055016000104).
200110032000202 is a wasteful number, since it uses less digits than its factorization.
200110032000202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100055016000103.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 200110032000202 its reverse (202000230011002), we get a palindrome (402110262011204).
The spelling of 200110032000202 in words is "two hundred trillion, one hundred ten billion, thirty-two million, two hundred two", and thus it is an aban number.
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