200111012101111 has 4 divisors (see below), whose sum is σ = 200184339700800. Its totient is φ = 200037684501424.

The previous prime is 200111012101109. The next prime is 200111012101123. The reversal of 200111012101111 is 111101210111002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200111012101111 - 2¹ = 200111012101109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200111012101091 and 200111012101100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200111012101811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36663795751 + ... + 36663801208.

It is an arithmetic number, because the mean of its divisors is an integer number (50046084925200).

Almost surely, 2^{200111012101111} is an apocalyptic number.

200111012101111 is a deficient number, since it is larger than the sum of its proper divisors (73327599689).

200111012101111 is an equidigital number, since it uses as much as digits as its factorization.

200111012101111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73327599688.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 200111012101111 its reverse (111101210111002), we get a palindrome (311212222212113).

The spelling of 200111012101111 in words is "two hundred trillion, one hundred eleven billion, twelve million, one hundred one thousand, one hundred eleven".