Base | Representation |
---|---|
bin | 1011101001011110001… |
… | …0111011100100001111 |
3 | 201010112002011200111002 |
4 | 2322113202323210033 |
5 | 11234311404341421 |
6 | 231532453250515 |
7 | 20312636352323 |
oct | 2722742734417 |
9 | 633462150432 |
10 | 200111012111 |
11 | 779594a424a |
12 | 32948933a3b |
13 | 15b4131a10a |
14 | 9984b3b983 |
15 | 53130a1b0b |
hex | 2e978bb90f |
200111012111 has 4 divisors (see below), whose sum is σ = 200162182224. Its totient is φ = 200059842000.
The previous prime is 200111012039. The next prime is 200111012131. The reversal of 200111012111 is 111210111002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200111012111 - 218 = 200110749967 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200111012092 and 200111012101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200111012131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25579190 + ... + 25587011.
It is an arithmetic number, because the mean of its divisors is an integer number (50040545556).
Almost surely, 2200111012111 is an apocalyptic number.
200111012111 is a deficient number, since it is larger than the sum of its proper divisors (51170113).
200111012111 is an equidigital number, since it uses as much as digits as its factorization.
200111012111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51170112.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 200111012111 its reverse (111210111002), we get a palindrome (311321123113).
The spelling of 200111012111 in words is "two hundred billion, one hundred eleven million, twelve thousand, one hundred eleven".
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