20011101220021 has 4 divisors (see below), whose sum is σ = 20350272427200. Its totient is φ = 19671930012844.

The previous prime is 20011101219997. The next prime is 20011101220039. The reversal of 20011101220021 is 12002210111002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20011101220021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20011101219983 and 20011101220010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20011101220321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169585603501 + ... + 169585603618.

It is an arithmetic number, because the mean of its divisors is an integer number (5087568106800).

Almost surely, 2^{20011101220021} is an apocalyptic number.

It is an amenable number.

20011101220021 is a deficient number, since it is larger than the sum of its proper divisors (339171207179).

20011101220021 is an equidigital number, since it uses as much as digits as its factorization.

20011101220021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339171207178.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 20011101220021 its reverse (12002210111002), we get a palindrome (32013311331023).

The spelling of 20011101220021 in words is "twenty trillion, eleven billion, one hundred one million, two hundred twenty thousand, twenty-one".