200111102113 has 4 divisors (see below), whose sum is σ = 215504263828. Its totient is φ = 184717940400.

The previous prime is 200111102069. The next prime is 200111102171. The reversal of 200111102113 is 311201111002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24208870464 + 175902231649 = 155592^2 + 419407^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200111102113 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 15393161701 = 200111102113 / (2 + 0 + 0 + 1 + 1 + 1 + 1 + 0 + 2 + 1 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200111102093 and 200111102102.

It is not an unprimeable number, because it can be changed into a prime (200111102183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7696580838 + ... + 7696580863.

It is an arithmetic number, because the mean of its divisors is an integer number (53876065957).

Almost surely, 2^200111102113 is an apocalyptic number.

It is an amenable number.

200111102113 is a deficient number, since it is larger than the sum of its proper divisors (15393161715).

200111102113 is a wasteful number, since it uses less digits than its factorization.

200111102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15393161714.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 200111102113 its reverse (311201111002), we get a palindrome (511312213115).

The spelling of 200111102113 in words is "two hundred billion, one hundred eleven million, one hundred two thousand, one hundred thirteen".