Base | Representation |
---|---|
bin | 1011101001011110011… |
… | …1000101011101100111 |
3 | 201010112011020000110120 |
4 | 2322113213011131213 |
5 | 11234312144214343 |
6 | 231532532453023 |
7 | 20312651536506 |
oct | 2722747053547 |
9 | 633464200416 |
10 | 200112101223 |
11 | 7795a078541 |
12 | 3294917a173 |
13 | 15b4160ba68 |
14 | 9984d4283d |
15 | 5313219683 |
hex | 2e979c5767 |
200112101223 has 4 divisors (see below), whose sum is σ = 266816134968. Its totient is φ = 133408067480.
The previous prime is 200112101213. The next prime is 200112101249. The reversal of 200112101223 is 322101211002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200112101223 - 226 = 200044992359 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200112101213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33352016868 + ... + 33352016873.
It is an arithmetic number, because the mean of its divisors is an integer number (66704033742).
Almost surely, 2200112101223 is an apocalyptic number.
200112101223 is a deficient number, since it is larger than the sum of its proper divisors (66704033745).
200112101223 is an equidigital number, since it uses as much as digits as its factorization.
200112101223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66704033744.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200112101223 its reverse (322101211002), we get a palindrome (522213312225).
The spelling of 200112101223 in words is "two hundred billion, one hundred twelve million, one hundred one thousand, two hundred twenty-three".
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