20011221012113 has 4 divisors (see below), whose sum is σ = 20032577705700. Its totient is φ = 19989864318528.

The previous prime is 20011221012071. The next prime is 20011221012169. The reversal of 20011221012113 is 31121012211002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6364055653264 + 13647165358849 = 2522708^2 + 3694207^2 .

It is a cyclic number.

It is not a de Polignac number, because 20011221012113 - 2⁴⁴ = 2419034967697 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20011221012091 and 20011221012100.

It is not an unprimeable number, because it can be changed into a prime (20011221012173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10678345388 + ... + 10678347261.

It is an arithmetic number, because the mean of its divisors is an integer number (5008144426425).

Almost surely, 2^{20011221012113} is an apocalyptic number.

It is an amenable number.

20011221012113 is a deficient number, since it is larger than the sum of its proper divisors (21356693587).

20011221012113 is an equidigital number, since it uses as much as digits as its factorization.

20011221012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21356693586.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 20011221012113 its reverse (31121012211002), we get a palindrome (51132233223115).

The spelling of 20011221012113 in words is "twenty trillion, eleven billion, two hundred twenty-one million, twelve thousand, one hundred thirteen".