Base | Representation |
---|---|
bin | 1011101001011110101… |
… | …0111001011000001111 |
3 | 201010112020002202221112 |
4 | 2322113222321120033 |
5 | 11234312423202203 |
6 | 231533010122235 |
7 | 20312663200334 |
oct | 2722752713017 |
9 | 633466082845 |
10 | 200113100303 |
11 | 7795a6a0126 |
12 | 3294958037b |
13 | 15b4189b72c |
14 | 998512298b |
15 | 53133656d8 |
hex | 2e97ab960f |
200113100303 has 4 divisors (see below), whose sum is σ = 210645368760. Its totient is φ = 189580831848.
The previous prime is 200113100293. The next prime is 200113100311. The reversal of 200113100303 is 303001311002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200113100303 - 212 = 200113096207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200113100903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5266134200 + ... + 5266134237.
It is an arithmetic number, because the mean of its divisors is an integer number (52661342190).
Almost surely, 2200113100303 is an apocalyptic number.
200113100303 is a deficient number, since it is larger than the sum of its proper divisors (10532268457).
200113100303 is a wasteful number, since it uses less digits than its factorization.
200113100303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10532268456.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 200113100303 its reverse (303001311002), we get a palindrome (503114411305).
The spelling of 200113100303 in words is "two hundred billion, one hundred thirteen million, one hundred thousand, three hundred three".
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