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20011312103 = 411014832483
BaseRepresentation
bin10010101000110001…
…000110001111100111
31220122121210222112112
4102220301012033213
5311440343441403
613105411511235
71305620226536
oct225061061747
956577728475
1020011312103
118539955a72
123a658b851b
131b6bb387a3
14d7b9cc31d
157c1c529d8
hex4a8c463e7

20011312103 has 8 divisors (see below), whose sum is σ = 20702361456. Its totient is φ = 19329928000.

The previous prime is 20011312073. The next prime is 20011312121. The reversal of 20011312103 is 30121311002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20011312103 - 218 = 20011049959 is a prime.

It is a super-2 number, since 2×200113121032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20011312133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2412101 + ... + 2420382.

It is an arithmetic number, because the mean of its divisors is an integer number (2587795182).

Almost surely, 220011312103 is an apocalyptic number.

20011312103 is a deficient number, since it is larger than the sum of its proper divisors (691049353).

20011312103 is a wasteful number, since it uses less digits than its factorization.

20011312103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4832625.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 20011312103 its reverse (30121311002), we get a palindrome (50132623105).

The spelling of 20011312103 in words is "twenty billion, eleven million, three hundred twelve thousand, one hundred three".

Divisors: 1 41 101 4141 4832483 198131803 488080783 20011312103