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2001140113 = 72437117307
BaseRepresentation
bin111011101000110…
…1111100110010001
312011110111110011111
41313101233212101
513044242440423
6530323213321
7100406260510
oct16721574621
95143443144
102001140113
11937656205
1247a217241
1325b78629b
1414dab4677
15baa3a60d
hex7746f991

2001140113 has 8 divisors (see below), whose sum is σ = 2287975232. Its totient is φ = 1714544496.

The previous prime is 2001140101. The next prime is 2001140129. The reversal of 2001140113 is 3110411002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2001140113 - 225 = 1967585681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2001140093 and 2001140102.

It is not an unprimeable number, because it can be changed into a prime (2001140413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41595 + ... + 75712.

It is an arithmetic number, because the mean of its divisors is an integer number (285996904).

Almost surely, 22001140113 is an apocalyptic number.

It is an amenable number.

2001140113 is a deficient number, since it is larger than the sum of its proper divisors (286835119).

2001140113 is a wasteful number, since it uses less digits than its factorization.

2001140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119751.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2001140113 is about 44734.1045847573. The cubic root of 2001140113 is about 1260.1604131451.

Adding to 2001140113 its reverse (3110411002), we get a palindrome (5111551115).

The spelling of 2001140113 in words is "two billion, one million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 7 2437 17059 117307 821149 285877159 2001140113