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200114325115 = 540022865023
BaseRepresentation
bin1011101001011110111…
…1100100011001111011
3201010112022102000001221
42322113233210121323
511234313231400430
6231533052252511
720313006461245
oct2722757443173
9633468360057
10200114325115
1177960357371
1232949a71137
1315b41c0a083
149985361095
15531350857a
hex2e97be467b

200114325115 has 4 divisors (see below), whose sum is σ = 240137190144. Its totient is φ = 160091460088.

The previous prime is 200114325097. The next prime is 200114325133. The reversal of 200114325115 is 511523411002.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (200114325097) and next prime (200114325133).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200114325115 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200114325115.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20011432507 + ... + 20011432516.

It is an arithmetic number, because the mean of its divisors is an integer number (60034297536).

Almost surely, 2200114325115 is an apocalyptic number.

200114325115 is a deficient number, since it is larger than the sum of its proper divisors (40022865029).

200114325115 is an equidigital number, since it uses as much as digits as its factorization.

200114325115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40022865028.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 200114325115 its reverse (511523411002), we get a palindrome (711637736117).

The spelling of 200114325115 in words is "two hundred billion, one hundred fourteen million, three hundred twenty-five thousand, one hundred fifteen".

Divisors: 1 5 40022865023 200114325115