Base | Representation |
---|---|
bin | 101101100000001000011000… |
… | …101110011101001001001011 |
3 | 222020120022000022112011200020 |
4 | 231200020120232131021023 |
5 | 202212232001440133003 |
6 | 1545341525303511523 |
7 | 60103126104203031 |
oct | 5540103056351113 |
9 | 866508008464606 |
10 | 200120121021003 |
11 | 58845515217327 |
12 | 1a5407537585a3 |
13 | 8788328569ac1 |
14 | 375bc19070551 |
15 | 18208b499cd53 |
hex | b60218b9d24b |
200120121021003 has 16 divisors (see below), whose sum is σ = 267058015948800. Its totient is φ = 133297851839040.
The previous prime is 200120121020999. The next prime is 200120121021011. The reversal of 200120121021003 is 300120121021002.
It is not a de Polignac number, because 200120121021003 - 22 = 200120121020999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200120121021013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21237423 + ... + 29176503.
It is an arithmetic number, because the mean of its divisors is an integer number (16691125996800).
Almost surely, 2200120121021003 is an apocalyptic number.
200120121021003 is a deficient number, since it is larger than the sum of its proper divisors (66937894927797).
200120121021003 is a wasteful number, since it uses less digits than its factorization.
200120121021003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7946362.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200120121021003 its reverse (300120121021002), we get a palindrome (500240242042005).
Subtracting 200120121021003 from its reverse (300120121021002), we obtain a palindrome (99999999999999).
The spelling of 200120121021003 in words is "two hundred trillion, one hundred twenty billion, one hundred twenty-one million, twenty-one thousand, three".
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