Base | Representation |
---|---|
bin | 101101100000001000011000… |
… | …101110011101001001010011 |
3 | 222020120022000022112011200112 |
4 | 231200020120232131021103 |
5 | 202212232001440133021 |
6 | 1545341525303511535 |
7 | 60103126104203042 |
oct | 5540103056351123 |
9 | 866508008464615 |
10 | 200120121021011 |
11 | 58845515217334 |
12 | 1a5407537585ab |
13 | 8788328569ac9 |
14 | 375bc19070559 |
15 | 18208b499cd5b |
hex | b60218b9d253 |
200120121021011 has 2 divisors, whose sum is σ = 200120121021012. Its totient is φ = 200120121021010.
The previous prime is 200120121020999. The next prime is 200120121021013. The reversal of 200120121021011 is 110120121021002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200120121021011 - 238 = 199845243114067 is a prime.
Together with 200120121021013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (200120121021013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060060510505 + 100060060510506.
It is an arithmetic number, because the mean of its divisors is an integer number (100060060510506).
Almost surely, 2200120121021011 is an apocalyptic number.
200120121021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
200120121021011 is an equidigital number, since it uses as much as digits as its factorization.
200120121021011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 200120121021011 its reverse (110120121021002), we get a palindrome (310240242042013).
Subtracting from 200120121021011 its reverse (110120121021002), we obtain a palindrome (90000000000009).
The spelling of 200120121021011 in words is "two hundred trillion, one hundred twenty billion, one hundred twenty-one million, twenty-one thousand, eleven".
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