Base | Representation |
---|---|
bin | 11101000111110000111… |
… | …000110010111110001011 |
3 | 21002022110011010210212102 |
4 | 131013300320302332023 |
5 | 230241430002311243 |
6 | 4131201131104015 |
7 | 264403426435514 |
oct | 35076070627613 |
9 | 7068404123772 |
10 | 2001201213323 |
11 | 701782a06174 |
12 | 283a1a2a200b |
13 | 116935391ba0 |
14 | 6cc04217a0b |
15 | 370c86a79b8 |
hex | 1d1f0e32f8b |
2001201213323 has 32 divisors (see below), whose sum is σ = 2245070115456. Its totient is φ = 1771638801408.
The previous prime is 2001201213307. The next prime is 2001201213353. The reversal of 2001201213323 is 3233121021002.
It is a cyclic number.
It is not a de Polignac number, because 2001201213323 - 24 = 2001201213307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001201213295 and 2001201213304.
It is not an unprimeable number, because it can be changed into a prime (2001201213353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60834386 + ... + 60867272.
It is an arithmetic number, because the mean of its divisors is an integer number (70158441108).
Almost surely, 22001201213323 is an apocalyptic number.
2001201213323 is a deficient number, since it is larger than the sum of its proper divisors (243868902133).
2001201213323 is a wasteful number, since it uses less digits than its factorization.
2001201213323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34743.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2001201213323 its reverse (3233121021002), we get a palindrome (5234322234325).
The spelling of 2001201213323 in words is "two trillion, one billion, two hundred one million, two hundred thirteen thousand, three hundred twenty-three".
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