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20012311343111 = 102433195369767
BaseRepresentation
bin1001000110011011110101…
…01101010111000000000111
32121212011021101102112110112
410203031322231113000013
510110340203200434421
6110321310124543235
74133561505510323
oct443157255270007
977764241375415
1020012311343111
1164161a004036a
1222b262a6b1b1b
13b221caab8349
144d285b362983
1524a875b0645b
hex12337ab57007

20012311343111 has 4 divisors (see below), whose sum is σ = 20012506815312. Its totient is φ = 20012115870912.

The previous prime is 20012311343107. The next prime is 20012311343161. The reversal of 20012311343111 is 11134311321002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20012311343111 - 22 = 20012311343107 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20012311343161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97582451 + ... + 97787316.

It is an arithmetic number, because the mean of its divisors is an integer number (5003126703828).

Almost surely, 220012311343111 is an apocalyptic number.

20012311343111 is a deficient number, since it is larger than the sum of its proper divisors (195472201).

20012311343111 is a wasteful number, since it uses less digits than its factorization.

20012311343111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195472200.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 20012311343111 its reverse (11134311321002), we get a palindrome (31146622664113).

The spelling of 20012311343111 in words is "twenty trillion, twelve billion, three hundred eleven million, three hundred forty-three thousand, one hundred eleven".

Divisors: 1 102433 195369767 20012311343111