Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …011010011010010011111 |
3 | 21002022112020121211011022 |
4 | 131013302223103102133 |
5 | 230242010143330421 |
6 | 4131204122314355 |
7 | 264404242534151 |
oct | 35076253232237 |
9 | 7068466554138 |
10 | 2001231230111 |
11 | 701798948233 |
12 | 283a283589bb |
13 | 11693b6716b9 |
14 | 6cc081ccad1 |
15 | 370cb1367ab |
hex | 1d1f2ad349f |
2001231230111 has 4 divisors (see below), whose sum is σ = 2011389764472. Its totient is φ = 1991072695752.
The previous prime is 2001231230059. The next prime is 2001231230129. The reversal of 2001231230111 is 1110321321002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2001231230111 - 210 = 2001231229087 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2001231230111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001231230161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5079266885 + ... + 5079267278.
It is an arithmetic number, because the mean of its divisors is an integer number (502847441118).
Almost surely, 22001231230111 is an apocalyptic number.
2001231230111 is a deficient number, since it is larger than the sum of its proper divisors (10158534361).
2001231230111 is a wasteful number, since it uses less digits than its factorization.
2001231230111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10158534360.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2001231230111 its reverse (1110321321002), we get a palindrome (3111552551113).
The spelling of 2001231230111 in words is "two trillion, one billion, two hundred thirty-one million, two hundred thirty thousand, one hundred eleven".
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