Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …011100110110100100010 |
3 | 21002022112020202212220101 |
4 | 131013302223212310202 |
5 | 230242010203410424 |
6 | 4131204124133014 |
7 | 264404243316331 |
oct | 35076253466442 |
9 | 7068466685811 |
10 | 2001231310114 |
11 | 7017989a2353 |
12 | 283a2839716a |
13 | 11693b69bc3a |
14 | 6cc0820dd18 |
15 | 370cb150344 |
hex | 1d1f2ae6d22 |
2001231310114 has 4 divisors (see below), whose sum is σ = 3001846965174. Its totient is φ = 1000615655056.
The previous prime is 2001231310081. The next prime is 2001231310121. The reversal of 2001231310114 is 4110131321002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1418731121025 + 582500189089 = 1191105^2 + 763217^2 .
It is a super-3 number, since 3×20012313101143 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001231310091 and 2001231310100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500307827527 + ... + 500307827530.
Almost surely, 22001231310114 is an apocalyptic number.
2001231310114 is a deficient number, since it is larger than the sum of its proper divisors (1000615655060).
2001231310114 is a wasteful number, since it uses less digits than its factorization.
2001231310114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1000615655059.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2001231310114 its reverse (4110131321002), we get a palindrome (6111362631116).
The spelling of 2001231310114 in words is "two trillion, one billion, two hundred thirty-one million, three hundred ten thousand, one hundred fourteen".
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