Base | Representation |
---|---|
bin | 11101000111110110111… |
… | …010011101000110000111 |
3 | 21002022201012101010020001 |
4 | 131013312322131012013 |
5 | 230242131342430203 |
6 | 4131215142022131 |
7 | 264406064653021 |
oct | 35076672350607 |
9 | 7068635333201 |
10 | 2001302311303 |
11 | 701824a87619 |
12 | 283a48117947 |
13 | 1169502cb389 |
14 | 6cc13813011 |
15 | 370d24c791d |
hex | 1d1f6e9d187 |
2001302311303 has 4 divisors (see below), whose sum is σ = 2001853486048. Its totient is φ = 2000751136560.
The previous prime is 2001302311291. The next prime is 2001302311313. The reversal of 2001302311303 is 3031132031002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2001302311303 - 213 = 2001302303111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001302311313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275581926 + ... + 275589187.
It is an arithmetic number, because the mean of its divisors is an integer number (500463371512).
Almost surely, 22001302311303 is an apocalyptic number.
2001302311303 is a deficient number, since it is larger than the sum of its proper divisors (551174745).
2001302311303 is an equidigital number, since it uses as much as digits as its factorization.
2001302311303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 551174744.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 2001302311303 its reverse (3031132031002), we get a palindrome (5032434342305).
The spelling of 2001302311303 in words is "two trillion, one billion, three hundred two million, three hundred eleven thousand, three hundred three".
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