200130301011133 has 4 divisors (see below), whose sum is σ = 200582062413408. Its totient is φ = 199678539608860.

The previous prime is 200130301011101. The next prime is 200130301011139. The reversal of 200130301011133 is 331110103031002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200130301011133 - 2⁵ = 200130301011101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200130301011133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200130301011139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225880700473 + ... + 225880701358.

It is an arithmetic number, because the mean of its divisors is an integer number (50145515603352).

Almost surely, 2^{200130301011133} is an apocalyptic number.

It is an amenable number.

200130301011133 is a deficient number, since it is larger than the sum of its proper divisors (451761402275).

200130301011133 is an equidigital number, since it uses as much as digits as its factorization.

200130301011133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451761402274.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 200130301011133 its reverse (331110103031002), we get a palindrome (531240404042135).

The spelling of 200130301011133 in words is "two hundred trillion, one hundred thirty billion, three hundred one million, eleven thousand, one hundred thirty-three".