Base | Representation |
---|---|
bin | 1001000110011101001110… |
… | …00100010000010111011111 |
3 | 2121212020012020202210110011 |
4 | 10203032213010100113133 |
5 | 10110343214204332001 |
6 | 110321512031424051 |
7 | 4133616113220505 |
oct | 443164704202737 |
9 | 77766166683404 |
10 | 20013055542751 |
11 | 6416542129597 |
12 | 22b27b7985027 |
13 | b222b903196b |
14 | 4d28cc124675 |
15 | 24a8bb109d51 |
hex | 1233a71105df |
20013055542751 has 4 divisors (see below), whose sum is σ = 20016088290000. Its totient is φ = 20010022795504.
The previous prime is 20013055542737. The next prime is 20013055542757. The reversal of 20013055542751 is 15724555031002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20013055542751 - 25 = 20013055542719 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20013055542757) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1516363726 + ... + 1516376923.
It is an arithmetic number, because the mean of its divisors is an integer number (5004022072500).
Almost surely, 220013055542751 is an apocalyptic number.
20013055542751 is a deficient number, since it is larger than the sum of its proper divisors (3032747249).
20013055542751 is an equidigital number, since it uses as much as digits as its factorization.
20013055542751 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3032747248.
The product of its (nonzero) digits is 210000, while the sum is 40.
The spelling of 20013055542751 in words is "twenty trillion, thirteen billion, fifty-five million, five hundred forty-two thousand, seven hundred fifty-one".
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