Base | Representation |
---|---|
bin | 101101100000010010101111… |
… | …101110110101000001101011 |
3 | 222020121100201112011000221220 |
4 | 231200102233232311001223 |
5 | 202212422242032204120 |
6 | 1545351005140433123 |
7 | 60104001542365305 |
oct | 5540225756650153 |
9 | 866540645130856 |
10 | 200131244413035 |
11 | 5884a203073401 |
12 | 1a5429389a87a3 |
13 | 87893abc08290 |
14 | 375c5924a0975 |
15 | 1820d162b2b40 |
hex | b604afbb506b |
200131244413035 has 32 divisors (see below), whose sum is σ = 344843292315648. Its totient is φ = 98525647244160.
The previous prime is 200131244413019. The next prime is 200131244413069. The reversal of 200131244413035 is 530314442131002.
It is not a de Polignac number, because 200131244413035 - 24 = 200131244413019 is a prime.
It is a super-2 number, since 2×2001312444130352 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200131244412987 and 200131244413005.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37146534 + ... + 42191556.
It is an arithmetic number, because the mean of its divisors is an integer number (10776352884864).
Almost surely, 2200131244413035 is an apocalyptic number.
200131244413035 is a deficient number, since it is larger than the sum of its proper divisors (144712047902613).
200131244413035 is a wasteful number, since it uses less digits than its factorization.
200131244413035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5248475.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 200131244413035 its reverse (530314442131002), we get a palindrome (730445686544037).
The spelling of 200131244413035 in words is "two hundred trillion, one hundred thirty-one billion, two hundred forty-four million, four hundred thirteen thousand, thirty-five".
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