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200131320001231 = 721169277509599
BaseRepresentation
bin101101100000010010110100…
…001111001011001011001111
3222020121100220210101022110201
4231200102310033023023033
5202212422420410014411
61545351020440514331
760104003451025123
oct5540226417131317
9866540823338421
10200131320001231
115884a241800993
121a54295a17b9a7
1387893c1782518
14375c59c539583
151820d1cc443c1
hexb604b43cb2cf

200131320001231 has 4 divisors (see below), whose sum is σ = 200131598232000. Its totient is φ = 200131041770464.

The previous prime is 200131320001211. The next prime is 200131320001241. The reversal of 200131320001231 is 132100023131002.

200131320001231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200131320001231 - 213 = 200131319993039 is a prime.

It is a super-2 number, since 2×2001313200012312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200131320001199 and 200131320001208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200131320001211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138033631 + ... + 139475968.

It is an arithmetic number, because the mean of its divisors is an integer number (50032899558000).

Almost surely, 2200131320001231 is an apocalyptic number.

200131320001231 is a deficient number, since it is larger than the sum of its proper divisors (278230769).

200131320001231 is an equidigital number, since it uses as much as digits as its factorization.

200131320001231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278230768.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 200131320001231 its reverse (132100023131002), we get a palindrome (332231343132233).

The spelling of 200131320001231 in words is "two hundred trillion, one hundred thirty-one billion, three hundred twenty million, one thousand, two hundred thirty-one".

Divisors: 1 721169 277509599 200131320001231