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200133340013 = 547365874479
BaseRepresentation
bin1011101001100011100…
…0000110101101101101
3201010120122012001121102
42322120320012231231
511234333113340023
6231535012012445
720313330215255
oct2723070065555
9633518161542
10200133340013
1177970064562
1232954301125
1315b45b36ca9
149987ab0965
155315012628
hex2e98e06b6d

200133340013 has 4 divisors (see below), whose sum is σ = 200499215040. Its totient is φ = 199767464988.

The previous prime is 200133340009. The next prime is 200133340081. The reversal of 200133340013 is 310043331002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200133340013 - 22 = 200133340009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200133040013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182936693 + ... + 182937786.

It is an arithmetic number, because the mean of its divisors is an integer number (50124803760).

Almost surely, 2200133340013 is an apocalyptic number.

It is an amenable number.

200133340013 is a deficient number, since it is larger than the sum of its proper divisors (365875027).

200133340013 is an equidigital number, since it uses as much as digits as its factorization.

200133340013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 365875026.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 200133340013 its reverse (310043331002), we get a palindrome (510176671015).

The spelling of 200133340013 in words is "two hundred billion, one hundred thirty-three million, three hundred forty thousand, thirteen".

Divisors: 1 547 365874479 200133340013