Base | Representation |
---|---|
bin | 11101000111111101000… |
… | …000011111000010101010 |
3 | 21002022222022202122210201 |
4 | 131013331000133002222 |
5 | 230242334031233214 |
6 | 4131233233302414 |
7 | 264411446012614 |
oct | 35077500370252 |
9 | 7068868678721 |
10 | 2001404555434 |
11 | 7018777710a9 |
12 | 283a76404a0a |
13 | 11696854946b |
14 | 6cc23229db4 |
15 | 370db472274 |
hex | 1d1fd01f0aa |
2001404555434 has 8 divisors (see below), whose sum is σ = 3002272575840. Its totient is φ = 1000647030156.
The previous prime is 2001404555419. The next prime is 2001404555477. The reversal of 2001404555434 is 4345554041002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 2001404555393 and 2001404555402.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27578484 + ... + 27650959.
It is an arithmetic number, because the mean of its divisors is an integer number (375284071980).
Almost surely, 22001404555434 is an apocalyptic number.
2001404555434 is a deficient number, since it is larger than the sum of its proper divisors (1000868020406).
2001404555434 is a wasteful number, since it uses less digits than its factorization.
2001404555434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55247564.
The product of its (nonzero) digits is 192000, while the sum is 37.
Adding to 2001404555434 its reverse (4345554041002), we get a palindrome (6346958596436).
It can be divided in two parts, 200140 and 4555434, that added together give a palindrome (4755574).
The spelling of 2001404555434 in words is "two trillion, one billion, four hundred four million, five hundred fifty-five thousand, four hundred thirty-four".
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