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200143030114411 = 577944134630171
BaseRepresentation
bin101101100000011101101110…
…001101101101100001101011
3222020122111010220000200212021
4231200131232031231201223
5202213120411202130121
61545400234433125311
760104566602242566
oct5540355615554153
9866574126020767
10200143030114411
115885420086627a
121a5450879b9837
13878a53984a487
14375cd8d8574dd
1518212a5d02641
hexb6076e36d86b

200143030114411 has 4 divisors (see below), whose sum is σ = 200143070524024. Its totient is φ = 200142989704800.

The previous prime is 200143030114387. The next prime is 200143030114451. The reversal of 200143030114411 is 114411030341002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200143030114411 - 229 = 200142493243499 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200143030114451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11535645 + ... + 23094526.

It is an arithmetic number, because the mean of its divisors is an integer number (50035767631006).

Almost surely, 2200143030114411 is an apocalyptic number.

200143030114411 is a deficient number, since it is larger than the sum of its proper divisors (40409613).

200143030114411 is an equidigital number, since it uses as much as digits as its factorization.

200143030114411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40409612.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 200143030114411 its reverse (114411030341002), we get a palindrome (314554060455413).

The spelling of 200143030114411 in words is "two hundred trillion, one hundred forty-three billion, thirty million, one hundred fourteen thousand, four hundred eleven".

Divisors: 1 5779441 34630171 200143030114411