2001433121331 has 16 divisors (see below), whose sum is σ = 3132229956864. Its totient is φ = 1112765904864.

The previous prime is 2001433121299. The next prime is 2001433121341. The reversal of 2001433121331 is 1331213341002.

It is not a de Polignac number, because 2001433121331 - 2⁵ = 2001433121299 is a prime.

It is a super-2 number, since 2×2001433121331² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2001433121341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1287922725 + ... + 1287924278.

It is an arithmetic number, because the mean of its divisors is an integer number (195764372304).

Almost surely, 2^{2001433121331} is an apocalyptic number.

2001433121331 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2001433121331 is a deficient number, since it is larger than the sum of its proper divisors (1130796835533).

2001433121331 is a wasteful number, since it uses less digits than its factorization.

2001433121331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2575847050.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 2001433121331 its reverse (1331213341002), we get a palindrome (3332646462333).

The spelling of 2001433121331 in words is "two trillion, one billion, four hundred thirty-three million, one hundred twenty-one thousand, three hundred thirty-one".