Base | Representation |
---|---|
bin | 101101100000011101111111… |
… | …011111101000001111001011 |
3 | 222020122111220002112122001212 |
4 | 231200131333133220033023 |
5 | 202213122004411232021 |
6 | 1545400323311003335 |
7 | 60104610022365230 |
oct | 5540357737501713 |
9 | 866574802478055 |
10 | 200143320024011 |
11 | 5885433a478691 |
12 | 1a545148b0954b |
13 | 878a584924510 |
14 | 375cdba161787 |
15 | 18212c14bb85b |
hex | b6077f7e83cb |
200143320024011 has 16 divisors (see below), whose sum is σ = 247754114268864. Its totient is φ = 157439806579584.
The previous prime is 200143320024007. The next prime is 200143320024013. The reversal of 200143320024011 is 110420023341002.
It is a cyclic number.
It is not a de Polignac number, because 200143320024011 - 22 = 200143320024007 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200143320024013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6356565596 + ... + 6356597081.
It is an arithmetic number, because the mean of its divisors is an integer number (15484632141804).
Almost surely, 2200143320024011 is an apocalyptic number.
200143320024011 is a deficient number, since it is larger than the sum of its proper divisors (47610794244853).
200143320024011 is a wasteful number, since it uses less digits than its factorization.
200143320024011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12713162870.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 200143320024011 its reverse (110420023341002), we get a palindrome (310563343365013).
The spelling of 200143320024011 in words is "two hundred trillion, one hundred forty-three billion, three hundred twenty million, twenty-four thousand, eleven".
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