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20014433483 = 111819493953
BaseRepresentation
bin10010101000111101…
…000000010011001011
31220122211200120021012
4102220331000103023
5311442143332413
613110002434135
71305655610012
oct225075002313
956584616235
1020014433483
118540698120
123a6696294b
131b6c68c465
14d7c1a1a79
157c216c7a8
hex4a8f404cb

20014433483 has 4 divisors (see below), whose sum is σ = 21833927448. Its totient is φ = 18194939520.

The previous prime is 20014433479. The next prime is 20014433519. The reversal of 20014433483 is 38433441002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20014433483 - 22 = 20014433479 is a prime.

It is a super-2 number, since 2×200144334832 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20014453483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 909746966 + ... + 909746987.

It is an arithmetic number, because the mean of its divisors is an integer number (5458481862).

Almost surely, 220014433483 is an apocalyptic number.

20014433483 is a deficient number, since it is larger than the sum of its proper divisors (1819493965).

20014433483 is a wasteful number, since it uses less digits than its factorization.

20014433483 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1819493964.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 20014433483 its reverse (38433441002), we get a palindrome (58447874485).

The spelling of 20014433483 in words is "twenty billion, fourteen million, four hundred thirty-three thousand, four hundred eighty-three".

Divisors: 1 11 1819493953 20014433483