Base | Representation |
---|---|
bin | 11101001000000001100… |
… | …101001010101001010011 |
3 | 21002100011200010200020101 |
4 | 131020001211022221103 |
5 | 230243013201430313 |
6 | 4131245013553231 |
7 | 264413400114625 |
oct | 35100145125123 |
9 | 7070150120211 |
10 | 2001481280083 |
11 | 7019070054aa |
12 | 283a98045817 |
13 | 11697b400a6c |
14 | 6cc2d4bcc15 |
15 | 370e307a5dd |
hex | 1d20194aa53 |
2001481280083 has 32 divisors (see below), whose sum is σ = 2164980787200. Its totient is φ = 1845536749056.
The previous prime is 2001481280077. The next prime is 2001481280107. The reversal of 2001481280083 is 3800821841002.
It is a cyclic number.
It is not a de Polignac number, because 2001481280083 - 213 = 2001481271891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2001481280053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 369478791 + ... + 369484207.
It is an arithmetic number, because the mean of its divisors is an integer number (67655649600).
Almost surely, 22001481280083 is an apocalyptic number.
2001481280083 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2001481280083 is a deficient number, since it is larger than the sum of its proper divisors (163499507117).
2001481280083 is a wasteful number, since it uses less digits than its factorization.
2001481280083 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10291.
The product of its (nonzero) digits is 24576, while the sum is 37.
The spelling of 2001481280083 in words is "two trillion, one billion, four hundred eighty-one million, two hundred eighty thousand, eighty-three".
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