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200167000051 = 641312273011
BaseRepresentation
bin1011101001101011100…
…0100000011111110011
3201010122222112011111111
42322122320200133303
511234420223000201
6231542213254151
720314216266424
oct2723270403763
9633588464444
10200167000051
1177988064877
1232963634357
1315b4cac0b85
14998c35364b
155317e60b51
hex2e9ae207f3

200167000051 has 4 divisors (see below), whose sum is σ = 200479273704. Its totient is φ = 199854726400.

The previous prime is 200167000043. The next prime is 200167000079. The reversal of 200167000051 is 150000761002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150000761002 = 275000380501.

It is a cyclic number.

It is not a de Polignac number, because 200167000051 - 23 = 200167000043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200166999986 and 200167000031.

It is not an unprimeable number, because it can be changed into a prime (200167000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156135865 + ... + 156137146.

It is an arithmetic number, because the mean of its divisors is an integer number (50119818426).

Almost surely, 2200167000051 is an apocalyptic number.

200167000051 is a deficient number, since it is larger than the sum of its proper divisors (312273653).

200167000051 is an equidigital number, since it uses as much as digits as its factorization.

200167000051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312273652.

The product of its (nonzero) digits is 420, while the sum is 22.

Adding to 200167000051 its reverse (150000761002), we get a palindrome (350167761053).

The spelling of 200167000051 in words is "two hundred billion, one hundred sixty-seven million, fifty-one", and thus it is an aban number.

Divisors: 1 641 312273011 200167000051