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200201313312 = 253472111373151
BaseRepresentation
bin1011101001110011101…
…1011001110000100000
3201010202101002110110000
42322130323121300200
511240003014011222
6231545440540000
720315114041200
oct2723473316040
9633671073400
10200201313312
11779a5470940
1232973021600
1315b56c46190
149992b26400
15531ae8c9ac
hex2e9ced9c20

200201313312 has 1440 divisors, whose sum is σ = 821079794304. Its totient is φ = 47029248000.

The previous prime is 200201313293. The next prime is 200201313329. The reversal of 200201313312 is 213313102002.

200201313312 is a `hidden beast` number, since 20 + 0 + 20 + 1 + 313 + 312 = 666.

200201313312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 1325836437 + ... + 1325836587.

Almost surely, 2200201313312 is an apocalyptic number.

200201313312 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200201313312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (410539897152).

200201313312 is an abundant number, since it is smaller than the sum of its proper divisors (620878480992).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200201313312 is a wasteful number, since it uses less digits than its factorization.

200201313312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 284 (or 260 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 200201313312 its reverse (213313102002), we get a palindrome (413514415314).

It can be divided in two parts, 200201313 and 312, that added together give a cube (200201625 = 5853).

The spelling of 200201313312 in words is "two hundred billion, two hundred one million, three hundred thirteen thousand, three hundred twelve".