Base | Representation |
---|---|
bin | 1011101001110101110… |
… | …0100010100100000011 |
3 | 201010202222102210112001 |
4 | 2322131130202210003 |
5 | 11240012230001011 |
6 | 231550351044431 |
7 | 20315250631201 |
oct | 2723534424403 |
9 | 633688383461 |
10 | 200210000131 |
11 | 779aa364429 |
12 | 32975b10717 |
13 | 15b589980cb |
14 | 9993d48071 |
15 | 531bb067c1 |
hex | 2e9d722903 |
200210000131 has 4 divisors (see below), whose sum is σ = 206668387264. Its totient is φ = 193751613000.
The previous prime is 200210000101. The next prime is 200210000201. The reversal of 200210000131 is 131000012002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200210000131 - 213 = 200209991939 is a prime.
It is a super-2 number, since 2×2002100001312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200210000101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3229193520 + ... + 3229193581.
It is an arithmetic number, because the mean of its divisors is an integer number (51667096816).
Almost surely, 2200210000131 is an apocalyptic number.
200210000131 is a deficient number, since it is larger than the sum of its proper divisors (6458387133).
200210000131 is an equidigital number, since it uses as much as digits as its factorization.
200210000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6458387132.
The product of its (nonzero) digits is 12, while the sum is 10.
Adding to 200210000131 its reverse (131000012002), we get a palindrome (331210012133).
The spelling of 200210000131 in words is "two hundred billion, two hundred ten million, one hundred thirty-one", and thus it is an aban number.
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