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20021012001213 = 36673670667071
BaseRepresentation
bin1001000110101100000010…
…10011101111000110111101
32121212222201202020202120220
410203112001103233012331
510111011013033014323
6110325305334131553
74134320225052426
oct443260123570675
977788652222526
1020021012001213
1164199553675a3
1222b42584b0bb9
13b22c8653b252
144d3044ad664d
1524abd48a40e3
hex1235814ef1bd

20021012001213 has 4 divisors (see below), whose sum is σ = 26694682668288. Its totient is φ = 13347341334140.

The previous prime is 20021012001197. The next prime is 20021012001217. The reversal of 20021012001213 is 31210021012002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20021012001213 - 24 = 20021012001197 is a prime.

It is a super-2 number, since 2×200210120012132 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20021012001192 and 20021012001201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20021012001217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3336835333533 + ... + 3336835333538.

It is an arithmetic number, because the mean of its divisors is an integer number (6673670667072).

Almost surely, 220021012001213 is an apocalyptic number.

It is an amenable number.

20021012001213 is a deficient number, since it is larger than the sum of its proper divisors (6673670667075).

20021012001213 is an equidigital number, since it uses as much as digits as its factorization.

20021012001213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6673670667074.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20021012001213 its reverse (31210021012002), we get a palindrome (51231033013215).

The spelling of 20021012001213 in words is "twenty trillion, twenty-one billion, twelve million, one thousand, two hundred thirteen".

Divisors: 1 3 6673670667071 20021012001213