Search a number
-
+
200210310211 = 1671198864133
BaseRepresentation
bin1011101001110101110…
…1101110010001000011
3201010210000000112212111
42322131131232101003
511240012314411321
6231550401440151
720315253362212
oct2723535562103
9633700015774
10200210310211
11779aa55639a
1232976040057
1315b58a762a2
149993dc9079
15531bb685e1
hex2e9d76e443

200210310211 has 4 divisors (see below), whose sum is σ = 201409174512. Its totient is φ = 199011445912.

The previous prime is 200210310203. The next prime is 200210310257. The reversal of 200210310211 is 112013012002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200210310211 - 23 = 200210310203 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200210310191 and 200210310200.

It is not an unprimeable number, because it can be changed into a prime (200210310281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 599431900 + ... + 599432233.

It is an arithmetic number, because the mean of its divisors is an integer number (50352293628).

Almost surely, 2200210310211 is an apocalyptic number.

200210310211 is a deficient number, since it is larger than the sum of its proper divisors (1198864301).

200210310211 is a wasteful number, since it uses less digits than its factorization.

200210310211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1198864300.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 200210310211 its reverse (112013012002), we get a palindrome (312223322213).

The spelling of 200210310211 in words is "two hundred billion, two hundred ten million, three hundred ten thousand, two hundred eleven".

Divisors: 1 167 1198864133 200210310211