Base | Representation |
---|---|
bin | 1001000110101100000110… |
… | …01111111001111001001101 |
3 | 2121212222211000111110211122 |
4 | 10203112003033321321031 |
5 | 10111011044401114440 |
6 | 110325312455530325 |
7 | 4134321101531453 |
oct | 443260317717115 |
9 | 77788730443748 |
10 | 20021044551245 |
11 | 6419971779951 |
12 | 22b42673899a5 |
13 | b22c901c6b1a |
14 | 4d304916a9d3 |
15 | 24abd76837b5 |
hex | 1235833f9e4d |
20021044551245 has 4 divisors (see below), whose sum is σ = 24025253461500. Its totient is φ = 16016835640992.
The previous prime is 20021044551149. The next prime is 20021044551257. The reversal of 20021044551245 is 54215544012002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13610329451524 + 6410715099721 = 3689218^2 + 2531939^2 .
It is a cyclic number.
It is not a de Polignac number, because 20021044551245 - 218 = 20021044289101 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002104455120 + ... + 2002104455129.
It is an arithmetic number, because the mean of its divisors is an integer number (6006313365375).
Almost surely, 220021044551245 is an apocalyptic number.
It is an amenable number.
20021044551245 is a deficient number, since it is larger than the sum of its proper divisors (4004208910255).
20021044551245 is an equidigital number, since it uses as much as digits as its factorization.
20021044551245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4004208910254.
The product of its (nonzero) digits is 64000, while the sum is 35.
Adding to 20021044551245 its reverse (54215544012002), we get a palindrome (74236588563247).
The spelling of 20021044551245 in words is "twenty trillion, twenty-one billion, forty-four million, five hundred fifty-one thousand, two hundred forty-five".
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