200211001212121 has 4 divisors (see below), whose sum is σ = 200212199107200. Its totient is φ = 200209803317044.

The previous prime is 200211001212073. The next prime is 200211001212179. The reversal of 200211001212121 is 121212100112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200211001212121 - 2⁷ = 200211001211993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200211001212095 and 200211001212104.

It is not an unprimeable number, because it can be changed into a prime (200211001212191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598696801 + ... + 599031118.

It is an arithmetic number, because the mean of its divisors is an integer number (50053049776800).

Almost surely, 2^{200211001212121} is an apocalyptic number.

It is an amenable number.

200211001212121 is a deficient number, since it is larger than the sum of its proper divisors (1197895079).

200211001212121 is a wasteful number, since it uses less digits than its factorization.

200211001212121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1197895078.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 200211001212121 its reverse (121212100112002), we get a palindrome (321423101324123).

The spelling of 200211001212121 in words is "two hundred trillion, two hundred eleven billion, one million, two hundred twelve thousand, one hundred twenty-one".