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2002110122011 = 14519137895869
BaseRepresentation
bin11101001000100111000…
…100000000100000011011
321002101210111102011012011
4131020213010000200123
5230300310142401021
64131431240130351
7264435104150206
oct35104704004033
97071714364164
102002110122011
117020a9a7277a
122840327669b7
13116a4b78748c
146cc8cc1293d
153712d393de1
hex1d22710081b

2002110122011 has 4 divisors (see below), whose sum is σ = 2002248032400. Its totient is φ = 2001972211624.

The previous prime is 2002110121997. The next prime is 2002110122027. The reversal of 2002110122011 is 1102210112002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002110122011 - 211 = 2002110119963 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002110121982 and 2002110122000.

It is not an unprimeable number, because it can be changed into a prime (2002110123011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68933416 + ... + 68962453.

It is an arithmetic number, because the mean of its divisors is an integer number (500562008100).

Almost surely, 22002110122011 is an apocalyptic number.

2002110122011 is a deficient number, since it is larger than the sum of its proper divisors (137910389).

2002110122011 is a wasteful number, since it uses less digits than its factorization.

2002110122011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137910388.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2002110122011 its reverse (1102210112002), we get a palindrome (3104320234013).

The spelling of 2002110122011 in words is "two trillion, two billion, one hundred ten million, one hundred twenty-two thousand, eleven".

Divisors: 1 14519 137895869 2002110122011