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2002110121997 is a prime number
BaseRepresentation
bin11101001000100111000…
…100000000100000001101
321002101210111102011011122
4131020213010000200031
5230300310142400442
64131431240130325
7264435104150156
oct35104704004015
97071714364148
102002110121997
117020a9a72767
122840327669a5
13116a4b78747b
146cc8cc1292d
153712d393dd2
hex1d22710080d

2002110121997 has 2 divisors, whose sum is σ = 2002110121998. Its totient is φ = 2002110121996.

The previous prime is 2002110121969. The next prime is 2002110122027. The reversal of 2002110121997 is 7991210112002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1192651831396 + 809458290601 = 1092086^2 + 899699^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002110121997 - 218 = 2002109859853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2002110121397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055060998 + 1001055060999.

It is an arithmetic number, because the mean of its divisors is an integer number (1001055060999).

Almost surely, 22002110121997 is an apocalyptic number.

It is an amenable number.

2002110121997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002110121997 is an equidigital number, since it uses as much as digits as its factorization.

2002110121997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 35.

Adding to 2002110121997 its reverse (7991210112002), we get a palindrome (9993320233999).

The spelling of 2002110121997 in words is "two trillion, two billion, one hundred ten million, one hundred twenty-one thousand, nine hundred ninety-seven".